Learn how searching and sorting algorithms actually work under the hood. No boring lectures, just pure logic, flowcharts, and visuals.
Before we jump into the algorithms, here is a 60-second crash course on the Python syntax you're going to see.
Basically a numbered bookshelf. Items start at position (index) `0`. If you want the first item, you ask for `[0]`.
Doing the same thing over and over. Use `for` when you know how many times to repeat. Use `while` to repeat until a condition is met.
How do you find a specific item in a massive list? It depends on if the list is organized or completely chaotic.
POV: You lost your AirPods in your messy room. You literally have to check under every pillow, inside every pocket, and under the bed, one by one, until you find them. Zero strategy, just checking everything.
target number.for loop to look at every index i from start to finish.if statement.return -1.
POV: You're looking up a word in a dictionary. You don't read page 1, page 2... You open to the middle. If your word starts with 'Z' and you're on 'M', you ignore the entire left half of the book. You just saved yourself reading 500 pages.
low (start) and high (end) variable.while low <= high loop. Keep searching as long as our window exists.mid. If arr[mid] is too small, move the left boundary (low = mid + 1). If too big, move the right boundary (high = mid - 1).
Turning chaos into order. Every algorithm here does the exact same job, but they have totally different "personalities" on how they achieve it.
This algorithm scans the whole crowd, points at the absolute smallest number, and says "You. Go to the front." Then it ignores the first spot, scans the rest, finds the next smallest, and puts it second. Very methodical, kinda slow.
for loop (i) representing where the next smallest number should go.i is the minimum. Use a second loop (j) starting from i+1 to scan the rest.min_idx. After the inner loop, swap them.
Literally just compares the person next to them. "Are you taller than me? Let's swap." By doing this repeatedly, the biggest numbers naturally "bubble" up to the very end of the list, like boba in a milk tea.
for loop).arr[j] > arr[j+1]. If they are out of order, swap them!n - i - 1. Why? Because after every pass, the biggest element is safely at the end.
Pick one random number (the pivot). Make everyone smaller stand to the left, and everyone bigger stand to the right. The pivot is now exactly where it belongs forever. Recursively do this for the left and right squads. Very fast. Very bossy.
pivot. Use pointer i to track where the "smaller than pivot" section ends.j), if a number is smaller than the pivot, swap it to the left side (index i+1).
Did you actually understand the algorithms, or were you just staring at the moving blocks? Let's find out.